This implements a symmetric boundary condition across the equator.
Specifically, the second last row of velocity points must be defined on
the equator (
). Note that the equator is at the
northern end of the domain. The condition applies when j in the
memory window corresponds to
jrow=jmt-1 and is given by
| ti,k,j+1,n | = | ti,k,j,n | |
| ui,k,j+1,1 | = | ui,k,j,1 | |
| ui,k,j+1,2 | = | -ui,k,j,2 | |
| psii,jrow+1 | = | -psii,jrow | |
| kmti,jrow+1 | = | kmti,jrow | (28.30) |